0=30x^2+598x-20

Solution for 0=30x^2+598x-20 equation:

0=30x^2+598x-20

We move all terms to the left:

0-(30x^2+598x-20)=0

We add all the numbers together, and all the variables

-(30x^2+598x-20)=0

We get rid of parentheses

-30x^2-598x+20=0

a = -30; b = -598; c = +20;
Δ = b2-4ac
Δ = -5982-4·(-30)·20
Δ = 360004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360004}=\sqrt{4*90001}=\sqrt{4}*\sqrt{90001}=2\sqrt{90001}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-598)-2\sqrt{90001}}{2*-30}=\frac{598-2\sqrt{90001}}{-60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-598)+2\sqrt{90001}}{2*-30}=\frac{598+2\sqrt{90001}}{-60}
$